Network

Rack Power and Cooling Calculator

Calculate rack power draw, heat output in BTU per hour, the circuits required with A and B feed redundancy, and the cooling capacity a room needs.

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All the power becomes heat

Electrical equipment converts essentially all of the energy it consumes into heat, so a rack drawing 8 kilowatts produces 8 kilowatts of heat, which is about 27,300 BTU per hour. Nothing meaningful leaves as light or motion. That means the cooling requirement is the power draw, and any room design that treats them as separate numbers has counted something twice or not at all. The only complication is that the cooling equipment itself consumes power and adds its own heat, which is what the power usage effectiveness ratio captures.

The eighty percent rule is a code requirement

A circuit supplying a continuous load, meaning three hours or more, must be loaded to no more than eighty percent of its rating under most electrical codes including the NEC. A 32 amp circuit therefore supplies 25.6 amps continuously, and sizing a rack to the nameplate rating rather than the derated figure produces a design that trips a breaker under sustained load. This is not a safety margin that can be spent; it is what the breaker is designed around.

Redundant feeds must each carry the whole load

A rack with A and B power feeds is only redundant if either feed alone can carry everything. That means each feed is loaded to at most fifty percent under normal operation, and the common error is loading each to eighty percent, which works until one feed fails and the other trips immediately. Dual corded equipment draws from both feeds simultaneously, so the measured draw per feed is roughly half the total, which makes the mistake easy to make and invisible until it matters.

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Frequently Asked Questions

How do I convert watts to BTU per hour?

Multiply by 3.412. All the electrical power a device consumes becomes heat, so a 5 kW rack produces 17,060 BTU per hour of cooling load. There is no separate heat calculation to do.

Why can I only load a circuit to 80 percent?

Because a load running three hours or more is continuous under most electrical codes, and a circuit supplying one must be derated to 80 percent of its rating. A 32 A breaker therefore supplies 25.6 A continuously. This is what the breaker is designed around rather than a margin to spend.

How should I load redundant power feeds?

Each feed to at most 50 percent, so either alone can carry the entire load. Loading each to 80 percent works normally and trips the survivor immediately when one feed fails, which is exactly when the redundancy was needed.

What is PUE?

Power usage effectiveness: total facility power divided by IT power. A PUE of 1.5 means half a watt of cooling and infrastructure for every watt of equipment. Modern purpose built data centres reach 1.1 to 1.3; a converted office room is commonly 2.0 or worse.

How many kilowatts can a rack take?

Traditional data centres design for 3 to 8 kW per rack with air cooling. Above about 15 kW containment becomes necessary, and above 30 kW air cooling stops being practical and liquid cooling is required. Dense GPU racks now reach 50 to 130 kW.

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How to Use

Add your equipment to calculate power draw, circuit requirements and cooling load.

Disclaimer: This tool is provided "as is" without warranty of any kind. Results are for educational and utility purposes.